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Translingual

Symbol

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   |-3| = 3

   The absolute value of minus three is three.

   For x = (1,1), and y = (4,5), |x – y| = √([1–4]² + [1–5]²) = 5

   For x equals one, one and y equals four, five, the absolute value of the quantity x minus y is the square root of (open parentheses) the quantity one minus four squared plus the quantity one minus five squared (close parentheses) or five.

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   |A|

   The determinant of the matrix A

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   $|\{3,5,7,9\}|=4$

   The set three, five, seven, and nine has a cardinality of four.

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   $\left|S^0\right|=2$

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