View source for Conull

==English==

===Etymology===
From {{prefix|en|co|null}}.

===Adjective===
{{wikipedia|Conull set|lang=en}}
{{en-adj|-}}

# {{lb|en|maths}} Having a [[null]] [[complement]]
#* {{quote-journal|en|year=2016|date=|author=Anton Bernshteyn|title=Measurable versions of the Lovász Local Lemma and measurable graph  colorings|journal=arXiv|url=http://arxiv.org/abs/1604.07349|doi=|volume=|issue=|pages=
|passage=Moreover, if the combinatorial structure on <math>X</math> is "induced" by the <math>[0;1]</math>-shift action of a countable group <math>\Gamma</math>, then, even without any local finiteness assumptions, there is a Borel choice for <math>f</math> which satisfies the constraints on an invariant '''conull''' set (i.e., with <math>\epsilon = 0</math>). }}